Selesai Masalah Matematik

hang19 · Post time 16-4-2008 12:18 AM

Originally posted by micha at 14-4-2008 09:06 PM
pakai equation sama,

2^x = 3^y = 6^z, express z in term of x n y

aku dapat z= ((y^2)/x) / log(2) x tau lar betol ker salah

Atomic_Omnikid · Post time 16-4-2008 12:55 AM

z=y/x

=1

micha · Post time 16-4-2008 01:41 AM

salah la u all. cube lg tau.....

hyie · Post time 18-4-2008 10:05 AM

micha xde soklan lg ke?

micha · Post time 19-4-2008 01:51 AM

soklan tu kan xjwb lg......

iqlima · Post time 24-4-2008 10:30 PM

z = xy/(x+y)
betul tak?

nafham · Post time 26-4-2008 12:09 AM

z=x=y, maka z = x-y or z = y-x

micha · Post time 27-4-2008 06:15 AM

yessssss, betul. tunjuk jln kira bleh. maybe org lain nk tau.

fiyass · Post time 27-4-2008 09:30 PM

best gak ek

iqlima · Post time 28-4-2008 12:08 AM

ni jalan kira...

2^x = 3^y = 6^z,  express z in term of x n y
log 2^x = log 3^y = log 6^z
x log 2 = y log 3 = z log 6

asingkan...
x log 2 = y log 3
x/y = log 3 / log 2
x = log 3
y = log 2

y log 3 = z  log 6
z = ( y log 3)/ log 6
z = ( y log 3)/ log 3 + log 2
substitute log 3 and log 2
z = xy/x +y

iqlima · Post time 28-4-2008 12:11 AM

micha...ada soalan lain tak ?

micha · Post time 28-4-2008 06:25 AM

nnt micha pk soklan lg k, kali nih nk bg kalkukus plak.

jeppa · Post time 2-5-2008 02:45 AM

Originally posted by iqlima at 28-4-2008 12:08 AM
ni jalan kira...

2^x = 3^y = 6^z, express z in term of x n y
log 2^x = log 3^y = log 6^z
x log 2 = y log 3 = z log 6

asingkan...
x l ...

baru nk jawab tapi dah ade org yg betul..

iqlima · Post time 3-5-2008 07:51 PM

hehehe...try la jwp guna kaedah lain sementara kita tunggu micha beri soalan lain...
ada dua kaedah lg yang boleh dibuat untuk jwp soalan nih...

pencil2b · Post time 22-7-2008 12:46 PM

setelah lama tinggalkan alam persekolahan...aku rasa mcm slow jer...mcm tak phm camana leh dpt jwpn camtu...takper..aku aku cube phmkan...bglah soklan lain micha..aku pun nak cerdaskan otak ni...